Knot Theory 3: Simplify, Simplify!
May. 26th, 2005 01:19 pmThe Story So Far: we've defined knots and links, and identified what it means for two knots to be equivalent. To study them more carefully, we've begun looking at plane representations of knots, and seen what that notion of equivalence translates to for plane representations: manipulation of the arcs between crossing points ("plane isotopy") and certain manipulations of the crossing points themselves ("Reidemeister moves").
Here's the problem. if two knots (or links) are equivalent, it's possible to manipulate any given plane representation of one, as just mentioned, so that it looks just like any given plane representation of the other. This is great, if you can come up with such a manipulation, but what if you can't? The best you can say, in that case, is that you don't know whether the knots are equivalent. We need a different, complementary approach, that of invariants. An invariant is a way of assigning, to any given knot or link, something - usually an algebraic object - in such a way that if two knots are equivalent the invariant assigns the same object to both. If you have an invariant, you can apply it to each of two knots; if the results are different, that tells you that the knots are not equivalent. (See the difference? The manipulation test is a way of showing that two knots are equivalent; invariants provide a way of showing that they aren't. The best of all situations is to have a complete set of invariants - one or more invariants with the property that, if each of them gives the same results to Knot1 and Knot2, then Knot1 and Knot2 are equivalent. Unfortunately, we don't have a complete set of invariants for knots as yet.)
To verify that a proposed invariant actually is an invariant, all we have to do is show that it isn't changed by plane isotopy or by Reidemeister moves. Since plane isotopy only affects the arcs in between crossing points, we can save time by looking at possible invariants which only look at the crossing points; then we only have to worry about the Reidemeister moves.
There are a number of known invariants for knots, but I'm only going to talk about one of them, the ( Jones polynomial. )
There are several other known invariants, all computed in similar ways; I hope the description under the cut gives some idea of the flavor of this sort of investigation.
Here's the problem. if two knots (or links) are equivalent, it's possible to manipulate any given plane representation of one, as just mentioned, so that it looks just like any given plane representation of the other. This is great, if you can come up with such a manipulation, but what if you can't? The best you can say, in that case, is that you don't know whether the knots are equivalent. We need a different, complementary approach, that of invariants. An invariant is a way of assigning, to any given knot or link, something - usually an algebraic object - in such a way that if two knots are equivalent the invariant assigns the same object to both. If you have an invariant, you can apply it to each of two knots; if the results are different, that tells you that the knots are not equivalent. (See the difference? The manipulation test is a way of showing that two knots are equivalent; invariants provide a way of showing that they aren't. The best of all situations is to have a complete set of invariants - one or more invariants with the property that, if each of them gives the same results to Knot1 and Knot2, then Knot1 and Knot2 are equivalent. Unfortunately, we don't have a complete set of invariants for knots as yet.)
To verify that a proposed invariant actually is an invariant, all we have to do is show that it isn't changed by plane isotopy or by Reidemeister moves. Since plane isotopy only affects the arcs in between crossing points, we can save time by looking at possible invariants which only look at the crossing points; then we only have to worry about the Reidemeister moves.
There are a number of known invariants for knots, but I'm only going to talk about one of them, the ( Jones polynomial. )
There are several other known invariants, all computed in similar ways; I hope the description under the cut gives some idea of the flavor of this sort of investigation.