stoutfellow: Joker (Default)
stoutfellow ([personal profile] stoutfellow) wrote2008-12-25 08:02 am
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Christmas

I may be fifty years old, but I was still the first one up this morning. By the time the others started stirring, I had had breakfast, read the paper, done the sudoku and the Times crossword, and solved a math problem[1].

No tree, no presents (since the gift exchange was last Saturday), but it's a good day. The Christmas Eve dinner was postponed to today for logistical reasons, so there's that to look forward to.

To those who celebrate the day, the merriest of Christmases; to those who do not, the merriest of Thursdays!

[1] It turns out that, if ABC is a triangle, the perpendicular bisector of BC and the angle bisector at A intersect at a point on the circumcircle of ABC. I'm pretty sure that it's the midpoint of the arc BC.

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